![]() The traveler would see no change between their speed and the speed of light. From the stationary observer's viewpoint the traveler's rate of acceleration would slow as they approached the speed of light. The greater the distance, the greater the speed from the stationary observer's viewpoint. The trip's duration from the traveler's viewpoint would be less due to the time dilation effect predicted by Einstein's Theory of Relativity. Proxima Centauri (4.2 light years) for example would take 5.2 years.īut that time is from the viewpoint of stationary observers at the departure point. Travel time (at 9.80665 m/s 2, decelerating halfway): 15d 7h 1m 12sĪccording to wikipedia, interstellar travel at 1G would take approximately 1 year + the distance in lightyears. Travel time (at 9.80665 m/s 2, decelerating halfway): 15d 7h 52m 48s Travel time (at 9.80665 m/s 2, decelerating halfway): 11d 20h 24m 0s Travel time (at 9.80665 m/s 2, no deceleration): 8d 9h 6m 0s ![]() Travel time (at 9.80665 m/s 2, decelerating halfway): 8d 2h 20m 24s Travel time (at 9.80665 m/s 2, no deceleration): 5d 17h 25m 1s Travel time (at 9.80665 m/s 2, decelerating halfway): 5d 16h 2m 2s Travel time (at 9.80665 m/s 2, no deceleration): 4d 0h 11m 2s Travel time (at 9.80665 m/s 2, decelerating halfway): 1d 21h 13m 1s Travel time (at 9.80665 m/s 2, no deceleration): 1d 7h 58m 5s Travel time (at 9.80665 m/s 2, decelerating halfway): 1d 11h 28m 48s Travel time (at 9.80665 m/s 2, no deceleration): 1d 1h 5m 2s Travel time (at 9.80665 m/s 2, decelerating halfway): 2d 1h 19m 12s Travel time (at 9.80665 m/s 2, decelerating halfway): 3h 20m 24s Travel time (at 9.80665 m/s 2, no deceleration): 2h 22m 12s literal constant 1g acceleration):Ĭlosest to Earth ( Supermoon): 356,577 km Not assuming any time taken for orbital maneuvering, turning halfway 180° to decelerate, assuming closest distance of planets (and Luna) to the Earth, and not accounting for fuel burn (i.e. There after we're moving at close to c, so add a little more than a year for each lightyear distance. 5 lightyears and our velocity will be close to maxed out. Our Newtonian model is okay for nearly a year of acceleration and after that relativity wrecks this nice parabola:Īfter 1 year at 1 g we will have traveled. But relativity won't allow that, we can only get close to c. In Newtonian mechanics v = at, so it'd take a little less than a year to reach c at 1 g acceleration. ![]() It gets trickier for interstellar distances. 9 days will get you 20 AU (more than halfway to the Kuiper belt) 4.5 days will get you 5 AU (halfway to Saturn). Using Days and AU (astronomical units) we can see 3 days will get about 2.5 AU (halfway to Jupiter). The other half distance spent decelerating would take the same amount of time. To travel half the distance to the moon would take about 1.75 hours. If you're using meters and seconds as your units, $a=9.8 meters/sec^2$ If you want the time it'd take for a specific distance, it's easy to manipulate $d=(1/2) a t^2$. So plotted over time, distance traveled is a nice parabola. Assuming acceleration is constant, $d=(1/2) a t^2$.
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